Can useQuery return/expose enabled/isEnabled, which is useful

[fritx]

In my project, most of useQuery are wrapped into new hooks and I have to manully return the enabled-prop like the code below.

If useQuery can expose enabled back to me, it will be fine.

In my case, I need enabled to judge if this query is in use or not.

export function useQueryOfMsSqlQueryDataSources({ sourceId }: { sourceId: string }) {
  const enabled = Boolean(sourceId);
  const ret = useQuery({
    enabled,
    queryKey: ['/data-source/mssql/query-data-sources', sourceId],
    queryFn: async () => {
      const res = await ...
      return res.data;
    },
  });
  return { ...ret, enabled };
}

[HectorMu]

Notice that your enabled derives from the sourceId, so if you follow this pattern, you could use the same parameter outside the hook to determine the query status

[fritx]

Hi, the below will be what I want, which is seamless,
if useQuery returns the enabled to me, then I don't need to retrive it and merge to return:

export function useQuery...({ sourceId }: { sourceId: string }) {
  return useQuery({
    enabled: Boolean(sourceId),
    queryKey: ['/data-source/mssql/query-data-sources', sourceId],
    queryFn: async () => {
      const res = await ...
      return res.data;
    },
  });
}

[fritx]

Also, I think the enabled is important in many scenarios so users can determine whether it is actually enabled and its isFetched, isSuccess, etc should be considered

[KutnerUri]

I second this - de-structuring ret is an anti pattern because it breaks rerender-optimizations.

while we could store enabled in a variable, and reuse it,

1. there's no easy way to return it together with useQuery result
2. it violates SRP - now I will have 2 places where I calculate enabled:

const enabled = ...;
const res =  useQuery({ enabled: enabled && oopsy });
return ..?;

so, it would be useful to return enabled (but not critical)

[TkDodo]

• feat(core): QueryObserver returns isEnabled flag #9408

[fritx]

Just found in code completion list in a random device. Thanks!