feat: add solutions to lc problem: No.1968

No.1968.Array With Elements Not Equal to Average of Neighbors

Author: yanglbme

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/README.md

@@ -65,6 +65,10 @@ i=3, nums[i] = 2, 两相邻元素平均值为 (6+0) / 2 = 3
 
 ### 方法一：排序
 
+由于数组中的元素是互不相同的，我们可以先对数组进行排序，然后将数组分成两部分，将前一半的元素放到答案数组中的偶数位置，将后一半的元素放到答案数组中的奇数位置。这样，对于每个元素，它的两个相邻元素都不会等于它的平均值。
+
+时间复杂度 $O(n \times \log n)$，空间复杂度 $O(n)$。其中 $n$ 是数组 $\textit{nums}$ 的长度。
+
 <!-- tabs:start -->
 
 #### Python3
@@ -74,7 +78,7 @@ class Solution:
     def rearrangeArray(self, nums: List[int]) -> List[int]:
         nums.sort()
         n = len(nums)
-        m = (n + 1) >> 1
+        m = (n + 1) // 2
         ans = []
         for i in range(m):
             ans.append(nums[i])
@@ -109,13 +113,15 @@ class Solution {
 class Solution {
 public:
     vector<int> rearrangeArray(vector<int>& nums) {
-        sort(nums.begin(), nums.end());
+        ranges::sort(nums);
         vector<int> ans;
         int n = nums.size();
         int m = (n + 1) >> 1;
         for (int i = 0; i < m; ++i) {
             ans.push_back(nums[i]);
-            if (i + m < n) ans.push_back(nums[i + m]);
+            if (i + m < n) {
+                ans.push_back(nums[i + m]);
+            }
         }
         return ans;
     }
@@ -125,46 +131,35 @@ public:
 #### Go
 
 ```go
-func rearrangeArray(nums []int) []int {
+func rearrangeArray(nums []int) (ans []int) {
 	sort.Ints(nums)
 	n := len(nums)
 	m := (n + 1) >> 1
-	var ans []int
 	for i := 0; i < m; i++ {
 		ans = append(ans, nums[i])
 		if i+m < n {
 			ans = append(ans, nums[i+m])
 		}
 	}
-	return ans
+	return
 }
 ```
 
-<!-- tabs:end -->
-
-<!-- solution:end -->
-
-<!-- solution:start -->
-
-### 方法二：随机打乱
-
-<!-- tabs:start -->
-
-#### Go
-
-```go
-func rearrangeArray(nums []int) []int {
-	rand.Seed(time.Now().UnixNano())
-outer:
-	for {
-		rand.Shuffle(len(nums), func(i, j int) { nums[i], nums[j] = nums[j], nums[i] })
-		for i := 1; i < len(nums)-1; i++ {
-			if nums[i]*2 == nums[i-1]+nums[i+1] {
-				continue outer
-			}
-		}
-		return nums
-	}
+#### TypeScript
+
+```ts
+function rearrangeArray(nums: number[]): number[] {
+    nums.sort((a, b) => a - b);
+    const n = nums.length;
+    const m = (n + 1) >> 1;
+    const ans: number[] = [];
+    for (let i = 0; i < m; i++) {
+        ans.push(nums[i]);
+        if (i + m < n) {
+            ans.push(nums[i + m]);
+        }
+    }
+    return ans;
 }
 ```
 

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/README_EN.md

@@ -63,7 +63,11 @@ When i=3, nums[i] = 2, and the average of its neighbors is (6+0) / 2 = 3.
 
 <!-- solution:start -->
 
-### Solution 1
+### Solution 1: Sorting
+
+Since the elements in the array are distinct, we can first sort the array, then divide the array into two parts. Place the first half of the elements in the even positions of the answer array, and the second half of the elements in the odd positions of the answer array. In this way, for each element, its two adjacent elements will not be equal to its average value.
+
+The time complexity is $O(n \times \log n)$, and the space complexity is $O(n)$. Here, $n$ is the length of the array $\textit{nums}$.
 
 <!-- tabs:start -->
 
@@ -74,7 +78,7 @@ class Solution:
     def rearrangeArray(self, nums: List[int]) -> List[int]:
         nums.sort()
         n = len(nums)
-        m = (n + 1) >> 1
+        m = (n + 1) // 2
         ans = []
         for i in range(m):
             ans.append(nums[i])
@@ -109,13 +113,15 @@ class Solution {
 class Solution {
 public:
     vector<int> rearrangeArray(vector<int>& nums) {
-        sort(nums.begin(), nums.end());
+        ranges::sort(nums);
         vector<int> ans;
         int n = nums.size();
         int m = (n + 1) >> 1;
         for (int i = 0; i < m; ++i) {
             ans.push_back(nums[i]);
-            if (i + m < n) ans.push_back(nums[i + m]);
+            if (i + m < n) {
+                ans.push_back(nums[i + m]);
+            }
         }
         return ans;
     }
@@ -125,46 +131,35 @@ public:
 #### Go
 
 ```go
-func rearrangeArray(nums []int) []int {
+func rearrangeArray(nums []int) (ans []int) {
 	sort.Ints(nums)
 	n := len(nums)
 	m := (n + 1) >> 1
-	var ans []int
 	for i := 0; i < m; i++ {
 		ans = append(ans, nums[i])
 		if i+m < n {
 			ans = append(ans, nums[i+m])
 		}
 	}
-	return ans
+	return
 }
 ```
 
-<!-- tabs:end -->
-
-<!-- solution:end -->
-
-<!-- solution:start -->
-
-### Solution 2
-
-<!-- tabs:start -->
-
-#### Go
-
-```go
-func rearrangeArray(nums []int) []int {
-	rand.Seed(time.Now().UnixNano())
-outer:
-	for {
-		rand.Shuffle(len(nums), func(i, j int) { nums[i], nums[j] = nums[j], nums[i] })
-		for i := 1; i < len(nums)-1; i++ {
-			if nums[i]*2 == nums[i-1]+nums[i+1] {
-				continue outer
-			}
-		}
-		return nums
-	}
+#### TypeScript
+
+```ts
+function rearrangeArray(nums: number[]): number[] {
+    nums.sort((a, b) => a - b);
+    const n = nums.length;
+    const m = (n + 1) >> 1;
+    const ans: number[] = [];
+    for (let i = 0; i < m; i++) {
+        ans.push(nums[i]);
+        if (i + m < n) {
+            ans.push(nums[i + m]);
+        }
+    }
+    return ans;
 }
 ```
 

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/Solution.cpp

@@ -1,14 +1,16 @@
 class Solution {
 public:
     vector<int> rearrangeArray(vector<int>& nums) {
-        sort(nums.begin(), nums.end());
+        ranges::sort(nums);
         vector<int> ans;
         int n = nums.size();
         int m = (n + 1) >> 1;
         for (int i = 0; i < m; ++i) {
             ans.push_back(nums[i]);
-            if (i + m < n) ans.push_back(nums[i + m]);
+            if (i + m < n) {
+                ans.push_back(nums[i + m]);
+            }
         }
         return ans;
     }
-};
+};

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/Solution.go

@@ -1,13 +1,12 @@
-func rearrangeArray(nums []int) []int {
+func rearrangeArray(nums []int) (ans []int) {
 	sort.Ints(nums)
 	n := len(nums)
 	m := (n + 1) >> 1
-	var ans []int
 	for i := 0; i < m; i++ {
 		ans = append(ans, nums[i])
 		if i+m < n {
 			ans = append(ans, nums[i+m])
 		}
 	}
-	return ans
-}
+	return
+}

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/Solution.py

@@ -2,7 +2,7 @@ class Solution:
     def rearrangeArray(self, nums: List[int]) -> List[int]:
         nums.sort()
         n = len(nums)
-        m = (n + 1) >> 1
+        m = (n + 1) // 2
         ans = []
         for i in range(m):
             ans.append(nums[i])

solution/1900-1999/1968.Array With Elements Not Equal to Average of Neighbors/Solution.ts

@@ -0,0 +1,13 @@
+function rearrangeArray(nums: number[]): number[] {
+    nums.sort((a, b) => a - b);
+    const n = nums.length;
+    const m = (n + 1) >> 1;
+    const ans: number[] = [];
+    for (let i = 0; i < m; i++) {
+        ans.push(nums[i]);
+        if (i + m < n) {
+            ans.push(nums[i + m]);
+        }
+    }
+    return ans;
+}