Improve inferrability #383
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There is no way to make the `S` keyword argument of `LinearOperator{T}`
inferrable.
This moves `S` to the second position, so anyone who wishes to write
inferrable code can use `LinearOperator{T, Vector{T}}(args...)`.
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There is no way to make the
Skeyword argument ofLinearOperator{T}inferrable.
This moves
Sto the second position, so anyone who wishes to writeinferrable code can use
LinearOperator{T, Vector{T}}(args...).