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IvanRenison
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It breaks the case when P is empty, but thats not an useful case

It breaks the case when P is empty, but thats not an useful case
@simonlindholm
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I don't care about the case of empty P, because that's not a tree, but I do care about sz(P) == 1. __lg(0) is undefined, right?

@IvanRenison
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IvanRenison commented May 12, 2024

Oh, yes, I saw in this stack overflow answer that it's -1, and in my machine gives -1, but according to this codeforces blog you are right.
I fixed it with sz(P) < 2 ? 0 :1 + __lg(sz(P) - 1)

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2 participants